C47 · Unit C10 Sequences and series
Taylor polynomials and Lagrange error
BC extensionReview editionNot yet human-reviewed
- Time
- About 45 minutes, untimed
- Course framework reference
- AP 10.11–10.12 · BC
- Part of
Progress on this lesson counts in every pathway listed.
Understand the idea
The degree-n Taylor polynomial at a is sum sub k ₌ sub 0 to the power n [f^(k)(a)/k!](x minus a)ᵏ. It matches the function’s derivatives through order n at a. If |f^(n+1)(t)| is less than or equal to M between a and x, Lagrange’s bound is |R_n(x)| is less than or equal to M|x minus a|^(n+1)/(n+1)!. A derivative bound must hold on the whole interval, not just at its center.
Worked example
The quadratic Maclaurin polynomial for eˣ is 1+x+x squared /2. At x equals 0.1 it gives 1.105. Since the third derivative is eᵗ is less than or equal to e to the power 0.1 on [0,0.1], the error is at most e to the power 0.1(0.1) cubed /6, approximately 0.0001842.
Explore the mathematics
Taylor polynomials and Lagrange error
Increase the degree of a polynomial approximation and check its error.
Scroll sideways to see the full diagram.
Predict before continuing
Predict where a polynomial built at zero approximates eˣ best.
Read the complete explanation
- Predict where a polynomial built at zero approximates eˣ best.
- Match the value and successive derivatives at the centre.
- Pₙ(x)=Σₖ₌₀ⁿxᵏ/k!. Orange is the polynomial; green is eˣ.
- At x=1 the error is 0.0516. A Lagrange bound on [0,1] is e/(n+1)!.
The exponential and quadratic Maclaurin approximation 1+x+x²/2 agree closely near zero. At x=0.1 the polynomial gives 1.105. The Lagrange estimate bounds the error by approximately 0.0001842; it is not the exact error.
Discuss: explain what each label represents, then draw a related example with different values.
A common misconception
Do not omit the factorial or the shift x minus a. A high polynomial degree does not by itself certify accuracy far from the center.
Investigate and explain
Compare a calculator error with the certified error bound. Explain why a conservative bound can still be useful.
Identify one step in the worked example, name the mathematical fact that permits it, and state its domain conditions.