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CalculusBy Educator Today

C12 · Unit C3 Composite, implicit and inverse derivatives

Inverse functions and inverse-trigonometric derivatives

CoreReview editionNot yet human-reviewed
Time
About 45 minutes, untimed
Course framework reference
AP 3.3–3.4
Builds on
Part of

Progress on this lesson counts in every pathway listed.

Understand the idea

If f is locally invertible and f minutes (a) is not equal to 0, then (f inverse) minutes (f(a)) equals 1 over f minutes (a). The input of the inverse derivative is the original output. Differentiating inverse identities gives (arcsin x) minutes equals 1/ square root of (1 minus x squared) for |x|<1 and (arctan x) minutes equals 1/(1+x squared). Arccos has the negative of the arcsin derivative.

Worked example

If f(2) equals 7 and f minutes (2) equals 3, then (f inverse) minutes (7) equals 1 over 3. For y equals arctan(2x), the chain rule gives y minutes equals 2/(1+4x squared). The denominator is positive for every real x.

Explore the mathematics

Inverse functions and inverse-trigonometric derivatives

Restrict a square function before comparing its inverse slopes.

Setting 3 of 5

Scroll sideways to see the full diagram.

Why must the square function have a restricted domain before inversion?xy12345f(x)=x² on x≥0; inverse f⁻¹(x)=√x

Predict before continuing

Why must the square function have a restricted domain before inversion?

Read the complete explanation
  1. Why must the square function have a restricted domain before inversion?
  2. Reflect a point (a,a²) across y=x to obtain (a²,a).
  3. At a>0 the two tangent slopes are reciprocals.
  4. The inverse slope at x=16 is 1/(2×4)=0.125. At a=0 the reciprocal rule is not applicable.
Inverse functions and inverse-trigonometric derivatives · visual worked method
Inverse functions and inverse-trigonometric derivatives · visual worked methodIf f(2)=7 and f′(2)=3, then (f⁻¹)′(7)=1/3. For y=arctan(2x), the chain rule gives y′=2/(1+4x²). The denominator is positive for every real x.Worked example · 1/2If f(2)=7 and f′(2)=3, then(f⁻¹)′(7)=1/3. For y=arctan(2x),the chain rule gives y′=2/(1+4x²).The denominator is positiveWorked example · 2/2for every real x.

If f(2)=7 and f′(2)=3, then (f⁻¹)′(7)=1/3. For y=arctan(2x), the chain rule gives y′=2/(1+4x²). The denominator is positive for every real x.

Discuss: explain what each label represents, then draw a related example with different values.

A common misconception

Do not compute 1 over f minutes (7) in the inverse example. First recover the original input whose output is 7.

Investigate and explain

Reflect a tangent line across y equals x. Connect reciprocal slopes to exchanging horizontal and vertical changes.
Identify one step in the worked example, name the mathematical fact that permits it, and state its domain conditions.